Reaction of propanamide with ethanolic sodium | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of an amide with bromine $(Br_2)$ in the presence of an aqueous or ethanolic solution of a strong base like sodium hydroxide $(NaOH)$

Vedclass · Accepted Answer

Ethylamine

Vedclass · Answer

(B) The reaction of an amide with bromine $(Br_2)$ in the presence of an aqueous or ethanolic solution of a strong base like sodium hydroxide $(NaOH)$ is known as the Hofmann bromamide degradation reaction.In this reaction,the amide is converted into a primary amine containing one carbon atom less than the original amide.The reaction for propanamide $(CH_3CH_2CONH_2)$ is:$CH_3CH_2CONH_2 + Br_2 + 4NaOH \rightarrow CH_3CH_2NH_2 + Na_2CO_3 + 2NaBr + 2H_2O$As shown in the reaction,propanamide ($3$ carbons) yields ethylamine ($2$ carbons).

Reaction of propanamide with ethanolic sodium hydroxide and bromine will give

Similar Questions

Gabriel phthalimide synthesis is used for the preparation of which of the following?

Which of the following can be prepared by the Gabriel phthalimide synthesis?

Which of the following compounds can be reduced to form a primary amine?

Identify $X$ and $Y$ in the following reactions:
$X \xrightarrow{H_2/Ni} CH_3CH_2CH_2NH_2 \xleftarrow{Br_2/NaOH} Y$

Find the suitable method from the following to prepare primary amines without the loss of carbons.

Vedclass Test Series

Exam Paper Generator

Online Exam Module