Reduction of aldehydes and ketones to hydrocarbons takes place in the presence of:

Match the reactants in Column-$I$ with their corresponding products in Column-$II$.

Acetone is treated with excess of ethanol in the presence of hydrochloric acid. The product obtained is

Comment on the stereochemistry of the products for the following reaction:
$3$-methylpentan-$2$-one + $CH_3MgBr$ followed by $NH_4Cl$ workup.

Benzyl alcohol and sodium benzoate are obtained by the action of sodium hydroxide on benzaldehyde. This reaction is known as

An organic compound $A$ on reaction with $PCC$ $(\text{Pyridinium chlorochromate})$ gives a compound $B$. $B$ on further reaction with $I_2$ and $NaOH$ forms tri-iodomethane. Identify the compound $A$.