Reduction of carboxylic acids gives

The major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$

Benzoic acid is treated with lithium aluminium hydride. The compound obtained is

For the following three esters, the order of rates of alkaline hydrolysis is:
$(I)$ $p-NO_2-C_6H_4-COOCH_3$
$(II)$ $p-CH_3O-C_6H_4-COOCH_3$
$(III)$ $p-CH_3-C_6H_4-COOCH_3$

Which of the following reacts with benzoic acid to form ethyl benzoate?

What is the order of reactivity of the following compounds towards sodalime decarboxylation?
$(i)$ $m$-nitro-phenylacetic acid
(ii) $p$-nitro-phenylacetic acid
(iii) $p$-methoxy-phenylacetic acid
(iv) $p$-methyl-phenylacetic acid