Resolving power of a telescope increases when

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(A) The resolving power $(RP)$ of a telescope is defined as the reciprocal of the minimum angular separation between two objects that can be just dist

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wavelength of light decreases.

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(A) The resolving power $(RP)$ of a telescope is defined as the reciprocal of the minimum angular separation between two objects that can be just distinguished by the telescope.It is given by the formula:$RP = \frac{D}{1.22 \lambda}$where $D$ is the diameter of the objective lens and $\lambda$ is the wavelength of light used.From the formula,it is clear that $RP \propto \frac{1}{\lambda}$.Therefore,when the wavelength of light $(\lambda)$ decreases,the resolving power of the telescope increases.

Similar Questions

The diameter of the objective lens of a telescope is $250\, cm$. For light of wavelength $600\, nm$ coming from a distant object, the limit of resolution of the telescope is close to:

Assume that light of wavelength $600\, nm$ is coming from a star. The limit of resolution of a telescope whose objective has a diameter of $2\, m$ is $......... \times 10^{-7}\, rad$.

The diameter of the objective of a telescope is $200 \text{ cm}$. What is the resolving power of the telescope? Take the wavelength of light $\lambda = 5000 \text{ \AA}$.

Two points separated by $0.05 \, mm$ can just be inspected in a microscope when light of wavelength $6000 \, \mathring{A}$ is used. If light of wavelength $3000 \, \mathring{A}$ is used,then the limit of resolution becomes ........... $mm$.

The resolving power of a microscope depends upon:

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