Same current is flowing in two different A.C. | vedclass

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(D) In an $A.C.$ circuit containing only an inductor, the inductive reactance is given by $X_L = 2\pi fL$. The current is $I = V / X_L = V / (2\pi fL)

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decrease in first circuit and increase in second.

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(D) In an $A.C.$ circuit containing only an inductor, the inductive reactance is given by $X_L = 2\pi fL$. The current is $I = V / X_L = V / (2\pi fL)$. As frequency $f$ increases, $X_L$ increases, so the current $I$ decreases.In an $A.C.$ circuit containing only a capacitor, the capacitive reactance is given by $X_C = 1 / (2\pi fC)$. The current is $I = V / X_C = V \cdot (2\pi fC)$. As frequency $f$ increases, $X_C$ decreases, so the current $I$ increases.Therefore, the current decreases in the first circuit and increases in the second circuit.

Same current is flowing in two different $A.C.$ circuits. The first circuit contains only an inductance $(L)$ and the second contains only a capacitance $(C)$. If the frequency of the $A.C.$ source is increased in both circuits, what will happen to the current?

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