Select the WRONG statement from the following | vedclass

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(C) For an isothermal process,the temperature $T$ remains constant.Since internal energy $U$ of an ideal gas depends only on temperature $(U = f(T))$,

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Equation of state $PV$ is not constant.

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(C) For an isothermal process,the temperature $T$ remains constant.Since internal energy $U$ of an ideal gas depends only on temperature $(U = f(T))$,the change in internal energy $\Delta U = 0$.According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$. Since $\Delta U = 0$,$\Delta Q = \Delta W$,meaning all energy exchanged is used to do work.An isothermal process requires the system to be in perfect thermal equilibrium with the environment to maintain a constant temperature.The equation of state for an ideal gas is $PV = nRT$. Since $n$,$R$,and $T$ are constant,$PV$ must be constant.Therefore,the statement '$PV$ is not constant' is incorrect.

Select the $WRONG$ statement from the following. For an isothermal process:

Similar Questions

Work done by a system under isothermal change from a volume $V_1$ to $V_2$ for a gas which obeys Van der Waals' equation $(V - n\beta) \left( P + \frac{\alpha n^2}{V^2} \right) = nRT$.

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The condition $dQ = dW$ holds good in which of the following?

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In which of the processes does the internal energy of the system remain constant?

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