The sequence 1, 3, 6, 10, ldots is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the nature of the sequence $1, 3, 6, 10, \ldots$,let us examine the differences between consecutive terms:$3 - 1 = 2$$6 - 3 = 3$$10 -

Vedclass · Accepted Answer

the sequence of triangular numbers

Vedclass · Answer

(D) To determine the nature of the sequence $1, 3, 6, 10, \ldots$,let us examine the differences between consecutive terms:$3 - 1 = 2$$6 - 3 = 3$$10 - 6 = 4$The differences are $2, 3, 4, \ldots$,which are not constant,so it is not an arithmetic progression.The ratios are $3/1 = 3$,$6/3 = 2$,$10/6 = 1.66$,which are not constant,so it is not a geometric progression.The Fibonacci sequence is defined by $F_n = F_{n-1} + F_{n-2}$,which does not match this pattern.These numbers are known as triangular numbers,defined by the formula $T_n = \frac{n(n+1)}{2}$.For $n=1, T_1 = 1$; for $n=2, T_2 = 3$; for $n=3, T_3 = 6$; for $n=4, T_4 = 10$. Thus,it is the sequence of triangular numbers.

The sequence $1, 3, 6, 10, \ldots$ is

Similar Questions

For an $A.P.$,$a=11$ and $d=7$. Find the sum of the first $40$ terms of the $A.P.$

For the finite $A.P.$ $1, 4, 7, \ldots, 118,$ find the $15^{th}$ term from the end.

Find the sum of the series: $7 + 10 \frac{1}{2} + 14 + \ldots + 84$.

Find the number of terms of the finite $A.P.$ $-1, -\frac{5}{6}, -\frac{2}{3}, \ldots, \frac{10}{3}$.

For a given $A.P.$,the first term is $-4$ and the common difference is $-5$. Then,the $12^{th}$ term of the $A.P.$ is $\ldots \ldots \ldots$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module