For an A.P.,a=11 and d=7. Find the sum of the | vedclass

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(A) The formula for the sum of the first $n$ terms of an $A.P.$ is given by $S_n = \frac{n}{2} [2a + (n - 1)d]$.Given values are $a = 11$,$d = 7$,and

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$5900$

Vedclass · Answer

(A) The formula for the sum of the first $n$ terms of an $A.P.$ is given by $S_n = \frac{n}{2} [2a + (n - 1)d]$.Given values are $a = 11$,$d = 7$,and $n = 40$.Substituting these values into the formula:$S_{40} = \frac{40}{2} [2(11) + (40 - 1)7]$$S_{40} = 20 [22 + (39 	imes 7)]$$S_{40} = 20 [22 + 273]$$S_{40} = 20 [295]$$S_{40} = 5900$.Therefore,the sum of the first $40$ terms is $5900$.

For an $A.P.$,$a=11$ and $d=7$. Find the sum of the first $40$ terms of the $A.P.$

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