Write the first three terms of the APs when a | vedclass

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(A) Given that,the first term $(a) = \sqrt{2}$ and the common difference $(d) = \frac{1}{\sqrt{2}}$.The general form of an $AP$ is $a, a+d, a+2d, \dot

Vedclass · Accepted Answer

$\sqrt{2}, \frac{3}{\sqrt{2}}, \frac{4}{\sqrt{2}}$

Vedclass · Answer

(A) Given that,the first term $(a) = \sqrt{2}$ and the common difference $(d) = \frac{1}{\sqrt{2}}$.The general form of an $AP$ is $a, a+d, a+2d, \dots$First term $(T_1) = a = \sqrt{2}$.Second term $(T_2) = a + d = \sqrt{2} + \frac{1}{\sqrt{2}} = \frac{(\sqrt{2} 	imes \sqrt{2}) + 1}{\sqrt{2}} = \frac{2+1}{\sqrt{2}} = \frac{3}{\sqrt{2}}$.Third term $(T_3) = a + 2d = \sqrt{2} + 2 	imes \frac{1}{\sqrt{2}} = \sqrt{2} + \frac{2}{\sqrt{2}} = \frac{(\sqrt{2} 	imes \sqrt{2}) + 2}{\sqrt{2}} = \frac{2+2}{\sqrt{2}} = \frac{4}{\sqrt{2}}$.Thus,the first three terms are $\sqrt{2}, \frac{3}{\sqrt{2}}, \frac{4}{\sqrt{2}}$.

Column $A$	Column $B$
$(A_{1}) \quad 2, -2, -6, -10, \ldots$	$(B_{1}) \quad \frac{2}{3}$
$(A_{2}) \quad a = -18, n = 10, a_{n} = 0$	$(B_{2}) \quad -5$
$(A_{3}) \quad a = 0, a_{10} = 6$	$(B_{3}) \quad 4$
$(A_{4}) \quad a_{2} = 13, a_{4} = 3$	$(B_{4}) \quad -4$
	$(B_{5}) \quad 2$
	$(B_{6}) \quad \frac{1}{2}$
	$(B_{7}) \quad 5$

Write the first three terms of the $APs$ when $a$ and $d$ are as given below:
$a=\sqrt{2}, d=\frac{1}{\sqrt{2}}$

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Write the first three terms of the $APs$ when $a$ and $d$ are as given below:$a=\sqrt{2}, d=\frac{1}{\sqrt{2}}$