Show the direction of the electric field that arises in a $p-n$ junction.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) When a $p-n$ junction is formed,electrons diffuse from the $n$-region to the $p$-region,and holes diffuse from the $p$-region to the $n$-region due to the concentration gradient.
This diffusion leaves behind ionized donor atoms (positive charges) in the $n$-region and ionized acceptor atoms (negative charges) in the $p$-region near the junction.
These immobile charges create an electric field directed from the $n$-region (positive side) to the $p$-region (negative side).
Therefore,the direction of the electric field in the depletion region of a $p-n$ junction is from the $n$-side to the $p$-side.

Explore More

Similar Questions

Which of the following diodes is reverse biased?

The forward biased diode connection is:

In the circuit shown in the figure,determine the voltage $V_0$ for the circuit network.

Difficult
View Solution

Two sides of a semiconductor germanium crystal $A$ and $B$ are doped with arsenic and indium respectively. They are connected to a battery as shown in the figure. The correct graph between current and voltage for the arrangement is:

In a $p-n$ junction diode, the thickness of the depletion layer is $2 \times 10^{-6} \,m$ and the barrier potential is $0.3 \,V$. The intensity of the electric field at the junction is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo