Simplify the following:(sqrt{3}-sqrt{2})^{2} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To simplify the expression $(\sqrt{3}-\sqrt{2})^{2}$,we use the algebraic identity $(a-b)^{2} = a^{2} + b^{2} - 2ab$.Here,$a = \sqrt{3}$ and $b =

Vedclass · Accepted Answer

$5-2\sqrt{6}$

Vedclass · Answer

(D) To simplify the expression $(\sqrt{3}-\sqrt{2})^{2}$,we use the algebraic identity $(a-b)^{2} = a^{2} + b^{2} - 2ab$.Here,$a = \sqrt{3}$ and $b = \sqrt{2}$.Substituting these values into the identity:$(\sqrt{3}-\sqrt{2})^{2} = (\sqrt{3})^{2} + (\sqrt{2})^{2} - 2(\sqrt{3})(\sqrt{2})$Since $(\sqrt{x})^{2} = x$ and $\sqrt{a} 	imes \sqrt{b} = \sqrt{ab}$:$= 3 + 2 - 2\sqrt{3 	imes 2}$$= 5 - 2\sqrt{6}$

Simplify the following:
$(\sqrt{3}-\sqrt{2})^{2}$

Similar Questions

Simplify: $5 \sqrt{2} + 2 \sqrt{8} - 3 \sqrt{32} + 4 \sqrt{128}$ (in $\sqrt{2}$)

Find the value of $64^{\frac{2}{3}}$.

Convert the following rational number into decimal form and state the kind of its decimal expansion:
$\frac{4}{13}$

Is $\sqrt{8+15}$ a rational number or an irrational number?

Simplify $7^{\frac{1}{4}} \cdot 12^{\frac{1}{4}}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Simplify the following:$(\sqrt{3}-\sqrt{2})^{2}$