Slope of the straight line obtained by plotting $\log_{10} k$ against $\frac{1}{T}$ represents which term?

For a reaction,the value of rate constant at $300 \ K$ is $6.0 \times 10^5 \ s^{-1}$. The value of Arrhenius factor $A$ at infinitely high temperature is

Activation energy is given by the formula

An increase in the concentration of the reactants of a reaction leads to a change in:

The rate of a reaction $A$ doubles on increasing the temperature from $300 \, K$ to $310 \, K$. By how much should the temperature of reaction $B$ be increased from $300 \, K$ so that its rate doubles,if the activation energy of reaction $B$ is twice that of reaction $A$ (in $, K$)?

With an increase in temperature,the rate constant $k$: