Sodium tertiary butoxide on reaction with met | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Reaction $1$: Sodium $t-butoxide$ $((CH_3)_3CONa)$ is a strong base and a bulky nucleophile. It reacts with methyl bromide $(CH_3Br)$ via an $S_N2

Vedclass · Accepted Answer

$P$ is $t-butyl$ methyl ether and $Q$ is $2-methylpropene$

Vedclass · Answer

(B) Reaction $1$: Sodium $t-butoxide$ $((CH_3)_3CONa)$ is a strong base and a bulky nucleophile. It reacts with methyl bromide $(CH_3Br)$ via an $S_N2$ mechanism to produce $t-butyl$ methyl ether $(CH_3-O-C(CH_3)_3)$ as the major product $(P)$.Reaction $2$: Sodium methoxide $(CH_3ONa)$ is a strong base. When it reacts with a tertiary substrate like $t-butyl$ bromide $((CH_3)_3CBr)$,the steric hindrance prevents $S_N2$ substitution. Instead,an $E2$ elimination reaction occurs,producing $2-methylpropene$ $((CH_3)_2C=CH_2)$ as the major product $(Q)$.

Sodium tertiary butoxide on reaction with methyl bromide produces the product $P$.
Sodium methoxide upon reaction with tertiary butyl bromide generates the product $Q$.
The products $P$ and $Q$ are

Similar Questions

$n$-propyl bromide on treatment with ethanolic potassium hydroxide produces

Which of the following represents the correct reactivity order for both $SN^1$ and $SN^2$ mechanisms?

Assertion : Benzyl bromide when kept in acetone water,it produces benzyl alcohol.
Reason : The reaction follows $S_{N}2$ mechanism.

$3$-Phenylpropene on reaction with $HBr$ gives (as a major product)

Explain the solubility of haloalkanes in water and organic solvents.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Sodium tertiary butoxide on reaction with methyl bromide produces the product $P$.Sodium methoxide upon reaction with tertiary butyl bromide generates the product $Q$.The products $P$ and $Q$ are