Solubility products of CuI and Ag_{2}CrO_{4} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For $CuI_{(s)} ightleftharpoons Cu^{+}_{(aq)} + I^{-}_{(aq)}$:$K_{sp} = [Cu^{+}][I^{-}] = x^{2} = 4 	imes 10^{-12}$$x = \sqrt{4 	imes 10^{-12}

Vedclass · Accepted Answer

$0.02$

Vedclass · Answer

(B) For $CuI_{(s)} ightleftharpoons Cu^{+}_{(aq)} + I^{-}_{(aq)}$:$K_{sp} = [Cu^{+}][I^{-}] = x^{2} = 4 	imes 10^{-12}$$x = \sqrt{4 	imes 10^{-12}} = 2 	imes 10^{-6} \ M$For $Ag_{2}CrO_{4(s)} ightleftharpoons 2Ag^{+}_{(aq)} + Cr{O_{4}}^{2-}_{(aq)}$:$K_{sp} = [Ag^{+}]^{2} [CrO_{4}^{2-}] = (2y)^{2}(y) = 4y^{3} = 4 	imes 10^{-12}$$y^{3} = 10^{-12} \implies y = 10^{-4} \ M$Ratio of solubilities $x/y = (2 	imes 10^{-6}) / (10^{-4}) = 2 	imes 10^{-2} = 0.02$.

Solubility products of $CuI$ and $Ag_{2}CrO_{4}$ have almost the same value $(\sim 4 \times 10^{-12})$. The ratio of solubilities of the two salts $(CuI : Ag_{2}CrO_{4})$ is closest to $....$

Similar Questions

$AgCl$ is soluble in:

At $T(K)$,the solubility product of $AgBr$ is $4 \times 10^{-13}$. What is its solubility in $0.1 \ M$ $KBr$ solution?

The correct representation for the solubility product of $SnS_2$ is:

The solubility of $AgCl$ at $20\,^oC$ is $1.435 \times 10^{-3} \, g/L$. The solubility product of $AgCl$ is .......

The solubility product of a sparingly soluble salt $AX_2$ is $3.2 \times 10^{-8}$. What is its solubility (in $mol \ dm^{-3}$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module