Solve the equation sqrt{2} x^{2} + x + sqrt{2 | vedclass

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(A) The given quadratic equation is $\sqrt{2} x^{2} + x + \sqrt{2} = 0$. On comparing the given equation with $ax^{2} + bx + c = 0$,we obtain $a = \sq

Vedclass · Accepted Answer

$\frac{-1 \pm \sqrt{7} i}{2 \sqrt{2}}$

Vedclass · Answer

(A) The given quadratic equation is $\sqrt{2} x^{2} + x + \sqrt{2} = 0$. On comparing the given equation with $ax^{2} + bx + c = 0$,we obtain $a = \sqrt{2}$,$b = 1$,and $c = \sqrt{2}$. The discriminant $D$ is given by $D = b^{2} - 4ac$. $D = (1)^{2} - 4(\sqrt{2})(\sqrt{2}) = 1 - 8 = -7$. The roots are given by the quadratic formula $x = \frac{-b \pm \sqrt{D}}{2a}$. $x = \frac{-1 \pm \sqrt{-7}}{2(\sqrt{2})} = \frac{-1 \pm \sqrt{7}i}{2\sqrt{2}}$.

Solve the equation $\sqrt{2} x^{2} + x + \sqrt{2} = 0$.

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