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(D) For the quadratic equation $am^{2} + bm + c = 0$,the quadratic formula is $m = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$.Here,$a = 48$,$b = -13$,and $

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$\frac{1}{3}, -\frac{1}{16}$

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(D) For the quadratic equation $am^{2} + bm + c = 0$,the quadratic formula is $m = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$.Here,$a = 48$,$b = -13$,and $c = -1$.First,calculate the discriminant $D = b^{2} - 4ac = (-13)^{2} - 4(48)(-1) = 169 + 192 = 361$.Since $D > 0$,real solutions exist.$m = \frac{-(-13) \pm \sqrt{361}}{2(48)} = \frac{13 \pm 19}{96}$.Case $1$: $m = \frac{13 + 19}{96} = \frac{32}{96} = \frac{1}{3}$.Case $2$: $m = \frac{13 - 19}{96} = \frac{-6}{96} = -\frac{1}{16}$.Thus,the solutions are $\frac{1}{3}$ and $-\frac{1}{16}$.

Solve the following quadratic equation using the quadratic formula,if the equation has a solution in $R$: $48m^{2} - 13m - 1 = 0$.

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