Solve the given two equations and select the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For equation $I$: $7x^{2} + 16x - 15 = 0$We factorize the quadratic equation: $7x^{2} + 21x - 5x - 15 = 0$$7x(x + 3) - 5(x + 3) = 0$$(7x - 5)(x +

Vedclass · Accepted Answer

if $x = y$ or relationship between $x$ and $y$ cannot be established.

Vedclass · Answer

(D) For equation $I$: $7x^{2} + 16x - 15 = 0$We factorize the quadratic equation: $7x^{2} + 21x - 5x - 15 = 0$$7x(x + 3) - 5(x + 3) = 0$$(7x - 5)(x + 3) = 0$So,$x = 5/7 \approx 0.71$ or $x = -3$.For equation $II$: $y^{2} - 6y - 7 = 0$We factorize the quadratic equation: $y^{2} - 7y + y - 7 = 0$$y(y - 7) + 1(y - 7) = 0$$(y + 1)(y - 7) = 0$So,$y = -1$ or $y = 7$.Comparing the values:If $x = 0.71$,then $x > y$ (for $y = -1$) and $x If $x = -3$,then $x Since the relationship changes depending on the values chosen,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and select the correct answer from the given options.
$I.$ $7x^{2} + 16x - 15 = 0$
$II.$ $y^{2} - 6y - 7 = 0$

Similar Questions

The length of a rectangular plot is $8 \, m$ greater than its breadth. If the area of the plot is $308 \, m^{2}$,find the length of the plot.

The roots of the equation $a^{2} x^{2}-3 a b x+2 b^{2}=0$ are

Solve the given two equations and select the correct option.

Solve the given two equations and select the correct answer from the given options.
$I. \quad 3x + 4y = (1681)^{1/2}$
$II. \quad 3x + 2y = (961)^{1/2}$

Solve the given two equations and select the correct answer from the given options.
$I.$ $\sqrt{25} x + \sqrt{16} y = 41$
$II.$ $\sqrt{16} x + \sqrt{25} y = 40$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Solve the given two equations and select the correct answer from the given options.$I.$ $7x^{2} + 16x - 15 = 0$$II.$ $y^{2} - 6y - 7 = 0$