Solve the given two equations and select the correct answer from the given options.
$I.$ $(17)^{2} + 144 \div 18 = x$
$II.$ $(26)^{2} - 18 \times 21 = y$
$I.$ $(17)^{2} + 144 \div 18 = x$
$II.$ $(26)^{2} - 18 \times 21 = y$
- A$x > y$
- B$x \geq y$
- C$x < y$
- D$x \leq y$
Explore More
Similar Questions
The roots of the equation $ix^2 - 4x - 4i = 0$ are
Medium
View SolutionThe sum of the roots of a quadratic equation is $2$ and the sum of their cubes is $98$. Then the equation is:
Easy
View SolutionWith respect to the roots of $x^{2}-x-2=0$,we can say that
Easy
View SolutionThe values of $a$ for which $(a^2 - 1)x^2 + 2(a - 1)x + 2$ is positive for any $x$ are
Medium
View SolutionThe quadratic equation with rational coefficients,whose one root is $\sqrt{5}$,is:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo