Solve the inequalities for real x: frac{5-3x} | vedclass

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Question

(A) Given inequality: $\frac{5-3x}{3} \leq \frac{x}{6}-5$. Multiply the entire inequality by $6$ to clear the denominators: $2(5-3x) \leq x - 30$. Exp

Vedclass · Accepted Answer

$x \in [\frac{40}{7}, \infty)$

Vedclass · Answer

(A) Given inequality: $\frac{5-3x}{3} \leq \frac{x}{6}-5$. Multiply the entire inequality by $6$ to clear the denominators: $2(5-3x) \leq x - 30$. Expand the terms: $10 - 6x \leq x - 30$. Rearrange the terms to isolate $x$: $10 + 30 \leq x + 6x$. $40 \leq 7x$. Divide by $7$: $x \geq \frac{40}{7}$. Thus,the solution set is $x \in [\frac{40}{7}, \infty)$.

Solve the inequalities for real $x$: $\frac{5-3x}{3} \leq \frac{x}{6}-5$.

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