Starch,when boiled with dilute sulphuric acid | vedclass

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Question

(A) Starch is a polysaccharide with the formula $(C_6H_{10}O_5)_n$. When starch is boiled with dilute $H_2SO_4$ under high pressure,it undergoes hydro

Vedclass · Accepted Answer

$CH_3-(CH_2)_4-CH_3$

Vedclass · Answer

(A) Starch is a polysaccharide with the formula $(C_6H_{10}O_5)_n$. When starch is boiled with dilute $H_2SO_4$ under high pressure,it undergoes hydrolysis to produce glucose $(A)$. The reaction is: $(C_6H_{10}O_5)_n + nH_2O \xrightarrow{	ext{dil. } H_2SO_4, 	ext{high pressure}} nC_6H_{12}O_6$. Glucose $(C_6H_{12}O_6)$,on prolonged heating with hydroiodic acid $(HI)$,undergoes reduction to form $n$-hexane $(B)$,which is $CH_3-(CH_2)_4-CH_3$. Therefore,the correct option is $A$.

Starch,when boiled with dilute sulphuric acid under high pressure,gives compound $A$. On prolonged heating with hydroiodic acid,$A$ gives compound $B$. What is the compound $B$?

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