The statement $(P$ $\Rightarrow Q) \wedge (R$ $\Rightarrow Q)$ is logically equivalent to:

  • A
    $(P \vee R) \Rightarrow Q$
  • B
    $(P$ $\Rightarrow R) \wedge (Q$ $\Rightarrow R)$
  • C
    $(P$ $\Rightarrow R) \vee (Q$ $\Rightarrow R)$
  • D
    $(P \wedge R) \Rightarrow Q$

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Similar Questions

The compound statement $(P \vee Q) \wedge (\sim P) \Rightarrow Q$ is equivalent to:

Consider the following statements.
$p$: If $3^4 > 4^3$, then $3^3 > 4^4$
$q$: The roots of the equation $x^2 - 2x + 2 = 0$ are real if and only if Mumbai is in Maharashtra.
$r$: Statement $p$ is true or statement $q$ is false.
Which of the following has truth value $T$ (true)?

The converse of the statement $((\sim p) \wedge q) \Rightarrow r$ is

Statement-$I$: $(p \wedge \sim q) \wedge (\sim p \wedge q)$ is a contradiction.
Statement-$II$: $(p$ $\rightarrow q) \Leftrightarrow (\sim q$ $\rightarrow \sim p)$ is a tautology.

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The conditional $(p \wedge q) \Rightarrow p$ is :-

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