Statement-I :- During propagation of electrom | vedclass

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(A) Statement-$I$ is true: In an electromagnetic wave,the electric field vector $\vec{E}$,the magnetic field vector $\vec{B}$,and the direction of wav

Vedclass · Accepted Answer

Both statement-$I$ and statement-$II$ are true.

Vedclass · Answer

(A) Statement-$I$ is true: In an electromagnetic wave,the electric field vector $\vec{E}$,the magnetic field vector $\vec{B}$,and the direction of wave propagation are mutually perpendicular to each other.Statement-$II$ is true: For an electromagnetic wave in vacuum,the average energy density associated with the electric field is $u_E = \frac{1}{2} \epsilon_0 E_{rms}^2$ and the average energy density associated with the magnetic field is $u_B = \frac{1}{2} \frac{B_{rms}^2}{\mu_0}$. Since $E_{rms} = c B_{rms}$ and $c = \frac{1}{\sqrt{\mu_0 \epsilon_0}}$,it follows that $u_E = u_B$. Thus,the energy is equally shared between the electric and magnetic fields.

Statement-$I$ :- During propagation of electromagnetic wave,$\vec{E}$,$\vec{B}$ and direction of propagation are perpendicular to each other.
Statement-$II$ :- During propagation of electromagnetic wave,the energy density due to electric and magnetic fields are equal.

Similar Questions

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Statement-$I$ :- During propagation of electromagnetic wave,$\vec{E}$,$\vec{B}$ and direction of propagation are perpendicular to each other.Statement-$II$ :- During propagation of electromagnetic wave,the energy density due to electric and magnetic fields are equal.