The statement $p \rightarrow \sim q$ is false,if

Let $p$: $A$ man is a judge.
$q$: He is honest.
The inverse of $p \rightarrow q$ is

The Boolean expression $\sim(p \vee q) \vee (\sim p \wedge q)$ is equivalent to:

By giving a counterexample,show that the following statement is false: "If $n$ is an odd integer,then $n$ is prime."

If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is false, then the truth values of $p \to q$ and $q \to p$ are respectively...

Find the function $f(x_{1}, x_{2}, x_{3})$ that satisfies $f(x_{1}, x_{2}, x_{3}) = 1$ at $x_{1} = 1, x_{2} = 0, x_{3} = 0$.