Which of the following is the strongest acid?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The acidity of carboxylic acids is determined by the stability of the conjugate base (carboxylate ion). Electron-withdrawing groups $(EWG)$ stabil

Vedclass · Accepted Answer

$CF_3COOH$

Vedclass · Answer

(A) The acidity of carboxylic acids is determined by the stability of the conjugate base (carboxylate ion). Electron-withdrawing groups $(EWG)$ stabilize the carboxylate ion through the inductive effect ($-I$ effect),thereby increasing acidity. The strength of the $-I$ effect depends on the electronegativity of the substituent. Fluorine $(F)$ is more electronegative than Chlorine $(Cl)$ and Bromine $(Br)$. Therefore,the $-I$ effect follows the order: $CF_3 > CCl_3 > CBr_3 > CH_3$. Thus,$CF_3COOH$ is the strongest acid among the given options.

Similar Questions

Which is the weakest acid among the following?

$2CH_3COOH \xrightarrow{P_2O_5} ........;$ What will be the product of this reaction?

Why is the ester hydrolysis slow in the beginning and becomes faster after sometime?

Identify $A$ and $B$ in the following reaction:
$CH_3-CH_3 \stackrel{B}{\longleftarrow} CH_3COOH \stackrel{A}{\longrightarrow} CH_3CH_2OH$
$A \quad B$

Which of the following reactions involves $\alpha$-halogenation of carboxylic acid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module