Sulphur trioxide is dissolved in heavy water | vedclass

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(B) When $SO_3$ is dissolved in heavy water $(D_2O)$,$D_2SO_4$ (deuterated sulphuric acid) is formed as the compound $X$.$SO_3 + D_2O \longrightarrow

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$sp^3$

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(B) When $SO_3$ is dissolved in heavy water $(D_2O)$,$D_2SO_4$ (deuterated sulphuric acid) is formed as the compound $X$.$SO_3 + D_2O \longrightarrow D_2SO_4 (X)$In $D_2SO_4$,the central sulphur atom is bonded to two $OD$ groups and two oxygen atoms via double bonds.The steric number of sulphur is $4$ (two single bonds and two double bonds,where double bonds count as one electron domain for hybridisation).Therefore,the hybridisation state of $S$ in $D_2SO_4$ is $sp^3$.

Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :

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