The sum of the absolute deviations is minimum when taken with respect to:

If the mode of a distribution is $18$ and the mean is $24$,then what is the median?

In a given frequency distribution,the respective values of mean and median are $21$ and $22$. The value of mode is

The mode of the following data set is $0, 1, 6, 7, 2, 3, 7, 6, 6, 2, 6, 0, 5, 6, 0$.

In a moderately asymmetrical distribution,the mode and mean are $7$ and $4$ respectively. The median is:

Consider the following frequency distribution:

Class	$0-6$	$6-12$	$12-18$	$18-24$	$24-30$
Frequency	$a$	$b$	$12$	$9$	$5$

If $\text{mean} = \frac{309}{22}$ and $\text{median} = 14$,then the value of $(a-b)^{2}$ is equal to $.....$