The system shown in the figure is in equilibr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Initially,the system is in equilibrium. The spring force $kx$ balances the total weight of the two masses.$kx = (2m + m)g = 3mg$Just after the str

Vedclass · Accepted Answer

$\frac{g}{2}$ upwards,$g$ downwards

Vedclass · Answer

(A) Initially,the system is in equilibrium. The spring force $kx$ balances the total weight of the two masses.$kx = (2m + m)g = 3mg$Just after the string is cut,the spring force remains unchanged because the spring cannot change its length instantaneously. The tension in the string becomes zero.For mass $m$ (lower block): The only force acting on it is gravity. Thus,its acceleration is $a_m = g$ downwards.For mass $2m$ (upper block): The forces acting on it are the spring force $kx$ upwards and gravity $2mg$ downwards.Using Newton's second law: $F_{	ext{net}} = ma$$kx - 2mg = (2m)a_{2m}$Substituting $kx = 3mg$:$3mg - 2mg = 2m \cdot a_{2m}$$mg = 2m \cdot a_{2m}$$a_{2m} = \frac{g}{2}$ upwards.Therefore,the acceleration of mass $2m$ is $\frac{g}{2}$ upwards and the acceleration of mass $m$ is $g$ downwards.

The system shown in the figure is in equilibrium and at rest. The spring and string are massless. Now,the string is cut. The acceleration of mass $2m$ and $m$ just after the string is cut will be:

Similar Questions

If $f(x) = \begin{cases} \frac{\sin(1+[x])}{[x]}, & \text{for } [x] \neq 0 \\ 0, & \text{for } [x] = 0 \end{cases}$ where $[x]$ denotes the greatest integer not exceeding $x$,then $\lim_{x \rightarrow 0^{-}} f(x)$ is equal to

The pair$(s)$ of diamagnetic ions is$(are)$
$(A) \ La ^{3+}, Ce ^{4+}$ $(B) \ Yb ^{2+}, Lu ^{3+}$ $(C) \ La ^{2+}, Ce ^{3+}$ $(D) \ Yb ^{3+}, Lu ^{2+}$

Which semi-dwarf variety of plant was developed by Nobel laureate Norman $E$. Borlaug?

From a disc of mass $M$ and radius $R$,a circular hole of diameter $R$ is cut such that its rim passes through the center of the disc. The moment of inertia of the remaining part of the disc about a perpendicular axis passing through the center of the original disc is

The energy of an electron in the $3^{rd}$ orbit of a hydrogenic atom is $-E$. The energy of an electron in the first orbit will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module