Take the breakdown voltage of the zener diode | vedclass

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(A) The circuit consists of two Zener diodes connected in series in reverse polarity. When the input voltage $V_{in}$ is positive, the first Zener dio

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(A) The circuit consists of two Zener diodes connected in series in reverse polarity. When the input voltage $V_{in}$ is positive, the first Zener diode is in reverse bias and the second is in forward bias. When $V_{in}$ exceeds the breakdown voltage of $6\, V$, the first Zener diode operates in the breakdown region, maintaining a constant output voltage of $6\, V$. When $V_{in}$ is between $0\, V$ and $6\, V$, the output voltage follows the input voltage. Similarly, when the input voltage $V_{in}$ is negative, the second Zener diode is in reverse bias and the first is in forward bias. When $V_{in}$ becomes more negative than $-6\, V$, the second Zener diode operates in the breakdown region, maintaining a constant output voltage of $-6\, V$. Thus, the output voltage is clipped at $+6\, V$ and $-6\, V$, resulting in a waveform that follows the input sine wave between $-6\, V$ and $+6\, V$ and remains constant at $\pm 6\, V$ outside this range. Comparing this with the given options, the correct graph is represented by option $A$.

Take the breakdown voltage of the zener diode used in the given circuit as $6\, V$. For the input voltage shown in the figure below, the time variation of the output voltage is: (Graphs drawn are schematic and not to scale)

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