The H-O-H bond angles in H_3O^+ are approxima | vedclass

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(D) In $H_3O^+$,the oxygen atom is bonded to three hydrogen atoms and has one lone pair of electrons.Using the formula for steric number: $Steric \ Nu

Vedclass · Accepted Answer

$sp^3-$ hybrid orbital

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(D) In $H_3O^+$,the oxygen atom is bonded to three hydrogen atoms and has one lone pair of electrons.Using the formula for steric number: $Steric \ Number = \frac{1}{2} [V + M - C + A] = \frac{1}{2} [6 + 3 - 1 + 0] = 4$.$A$ steric number of $4$ corresponds to $sp^3$ hybridization.The geometry is pyramidal with a bond angle of approximately $107^\circ$ due to the presence of one lone pair,which causes repulsion.Therefore,the orbitals used by oxygen are $sp^3$ hybrid orbitals.

List-$I$ (Species)	List-$II$ (Hybrid Orbitals)
$(a)$ $SF_{4}$	$(i)$ $sp^{3}d^{2}$
$(b)$ $IF_{5}$	$(ii)$ $d^{2}sp^{3}$
$(c)$ $NO_{2}^{+}$	$(iii)$ $sp^{3}d$
$(d)$ $NH_{4}^{+}$	$(iv)$ $sp^{3}$
	$(v)$ $sp$

The $H-O-H$ bond angles in $H_3O^+$ are approximately $107^\circ$. The orbitals used by oxygen in these bonds are best described as

Similar Questions

Match List-$I$ with List-$II$ :

List-$I$ (Species) List-$II$ (Hybrid Orbitals)

$(a)$ $SF_{4}$ $(i)$ $sp^{3}d^{2}$

$(b)$ $IF_{5}$ $(ii)$ $d^{2}sp^{3}$

$(c)$ $NO_{2}^{+}$ $(iii)$ $sp^{3}d$

$(d)$ $NH_{4}^{+}$ $(iv)$ $sp^{3}$

$(v)$ $sp$

Choose the correct answer from the options given below :

Chlorine atom,in its third excited state,reacts with fluorine to form a compound $X$. The formula and shape of $X$ are :

Which of the following conversions involves a change in both shape and hybridisation?

The hybridisations of $N$-orbitals in $NO_3^{-}$,$NO_2^{-}$ and $NH_4^{+}$ respectively are

What are the shapes of $sp$,$sp^2$,and $sp^3$ hybrid orbitals?

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