The hybridisations of N-orbitals in NO_3^{-}, | vedclass

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(A) The hybridisation can be calculated using the formula: $H = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electrons of the centr

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$sp^2, sp^2, sp^3$

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(A) The hybridisation can be calculated using the formula: $H = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $NO_3^{-}$: $H = \frac{1}{2} [5 + 0 - 0 + 1] = 3$,which corresponds to $sp^2$ hybridisation.For $NO_2^{-}$: $H = \frac{1}{2} [5 + 0 - 0 + 1] = 3$,which corresponds to $sp^2$ hybridisation.For $NH_4^{+}$: $H = \frac{1}{2} [5 + 4 - 1 + 0] = 4$,which corresponds to $sp^3$ hybridisation.Thus,the hybridisations are $sp^2, sp^2$ and $sp^3$ respectively.

The hybridisations of $N$-orbitals in $NO_3^{-}$,$NO_2^{-}$ and $NH_4^{+}$ respectively are

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