The x-t equation is given as x = 2t + 1. The | vedclass

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(B) Given the position-time equation: $x = 2t + 1$.To find the velocity $v$,we differentiate $x$ with respect to time $t$:$v = \frac{dx}{dt} = \frac{d

Vedclass · Accepted Answer

a straight line not passing through origin

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(B) Given the position-time equation: $x = 2t + 1$.To find the velocity $v$,we differentiate $x$ with respect to time $t$:$v = \frac{dx}{dt} = \frac{d}{dt}(2t + 1) = 2 \, m/s$.Since the velocity $v = 2 \, m/s$ is a constant value independent of time $t$,the $v-t$ graph will be a horizontal straight line parallel to the time axis.$A$ horizontal line at $v = 2$ does not pass through the origin $(0,0)$.Therefore,the correct option is $B$.

The $x-t$ equation is given as $x = 2t + 1$. The corresponding $v-t$ graph is:

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