The $Ca^{2+}$ and $F^{-}$ ions are located in $CaF_2$ crystal,respectively,at face-centered cubic lattice points and in

The crystal $AB$ has a structure similar to $NaCl$. Atoms of $A$ are present at each corner of the cubic unit cell. If all atoms along one of the axes passing through the face centers are removed,what will be the resulting stoichiometry?

If $a$ is the length of the side of a cube,the distance between the body-centered atom and one corner atom in the cube will be

What is the coordination number of $Cs^{+}$ and $Cl^{-}$ ions in the $CsCl$ structure?

An alloy made up of $A$ and $B$ metals crystallises in a cubic lattice, where $B$ atoms occupy the corners and $A$ atoms occupy the face centers. The formula of the alloy formed is

$A$ compound formed by elements $A$ and $B$ crystallizes in a cubic structure where $A$ atoms are at the corners of the cube and $B$ atoms are at the center of the cube. What is the formula of the compound?