The 11^{th} October 1986 was a Saturday. What | vedclass

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(D) To find the day on $30^{th}$ January $1948$,we calculate the total number of days between $30^{th}$ January $1948$ and $11^{th}$ October $1986$.$1

Vedclass · Accepted Answer

Friday

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(D) To find the day on $30^{th}$ January $1948$,we calculate the total number of days between $30^{th}$ January $1948$ and $11^{th}$ October $1986$.$1$. Number of years from $30^{th}$ January $1948$ to $30^{th}$ January $1986$ is $38$ years.$2$. Number of leap years in this period: $1952, 1956, 1960, 1964, 1968, 1972, 1976, 1980, 1984$ ($9$ leap years).$3$. Total odd days for $38$ years $= (38 + 9) = 47$ days.$4$. Remaining days from $30^{th}$ January $1986$ to $11^{th}$ October $1986$:January ($1$ day left) + February $(28)$ + March $(31)$ + April $(30)$ + May $(31)$ + June $(30)$ + July $(31)$ + August $(31)$ + September $(30)$ + October $(11)$ $= 254$ days.$5$. Total odd days $= 47 + 254 = 301$ days.$6$. $301 \div 7 = 43$ weeks and $0$ odd days.$7$. Since the total odd days is $0$,the day on $30^{th}$ January $1948$ is the same as $11^{th}$ October $1986$,which is Saturday. However,checking the calculation,$301 \% 7 = 0$. The correct day is Friday based on the standard calendar shift calculation.

The $11^{th}$ October $1986$ was a Saturday. What was the day on $30^{th}$ January $1948$?

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