(B) Let the two numbers be $1x$ and $4x$ respectively.We know that the product of two numbers is equal to the product of their $H.C.F.$ and $L.C.M.$Th

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(B) Let the two numbers be $1x$ and $4x$ respectively.We know that the product of two numbers is equal to the product of their $H.C.F.$ and $L.C.M.$Therefore,$(1x) \times (4x) = 21 \times 84$$4x^2 = 1764$$x^2 = \frac{1764}{4} = 441$$x = \sqrt{441} = 21$The two numbers are $1 \times 21 = 21$ and $4 \times 21 = 84$.The larger number is $84$.