The 11^{text{th}} term of the AP: -5, frac{-5 | vedclass

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Question

(B) Given $AP$ is $-5, \frac{-5}{2}, 0, \frac{5}{2}, \dots$Here,the first term $a = -5$.The common difference $d = \frac{-5}{2} - (-5) = \frac{-5}{2}

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(B) Given $AP$ is $-5, \frac{-5}{2}, 0, \frac{5}{2}, \dots$Here,the first term $a = -5$.The common difference $d = \frac{-5}{2} - (-5) = \frac{-5}{2} + 5 = \frac{-5 + 10}{2} = \frac{5}{2}$.The formula for the $n^{	ext{th}}$ term of an $AP$ is $a_n = a + (n - 1)d$.To find the $11^{	ext{th}}$ term $(n = 11)$:$a_{11} = -5 + (11 - 1) 	imes \frac{5}{2}$$a_{11} = -5 + 10 	imes \frac{5}{2}$$a_{11} = -5 + 5 	imes 5$$a_{11} = -5 + 25$$a_{11} = 20$.

The $11^{\text{th}}$ term of the $AP: -5, \frac{-5}{2}, 0, \frac{5}{2}, \dots$ is

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