The $3d$ metal ions form coloured compounds because the energy corresponding to the following lies in the visible range of the electromagnetic spectrum:

  • A
    Free energy change of complex formation by $3d$ metal ions
  • B
    $d-d$ transitions of $3d$ electrons
  • C
    Heat of hydration of $3d$ metal ions
  • D
    Ionisation energy of $3d$ metal ions

Explore More

Similar Questions

Which of the following is the correct order of ligand field strength?

The order of energy absorbed,which is responsible for the color of the following complexes,is:

If $[Cu(H_{2}O)_{4}]^{2+}$ absorbs light of wavelength $600 \ nm$ for $d-d$ transition,then the value of octahedral crystal field splitting energy for $[Cu(H_{2}O)_{6}]^{2+}$ will be $..... \times 10^{-21} \ J$. (Nearest Integer)
(Given: $h = 6.63 \times 10^{-34} \ Js$ and $c = 3.08 \times 10^{8} \ ms^{-1}$)

In which of the following octahedral complex species the magnitude of $\Delta_0$ will be maximum?

Simplified absorption spectra of three complexes $(i), (ii)$ and $(iii)$ of $M^{n+}$ ion are provided below; their $\lambda_{max}$ values are marked as $A, B$ and $C$ respectively. The correct match between the complexes and their $\lambda_{max}$ values is
$(i)$ $[M(NCS)_6]^{(-6+n)}$
$(ii)$ $[MF_6]^{(-6+n)}$
$(iii)$ $[M(NH_3)_6]^{n+}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo