The P-V diagram of a system undergoing thermo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$. Here,$\Delta Q$ is the heat given to the system,$\Delta U$ is the c

Vedclass · Accepted Answer

$134$

Vedclass · Answer

(D) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$. Here,$\Delta Q$ is the heat given to the system,$\Delta U$ is the change in internal energy,and $\Delta W$ is the work done $BY$ the system. Given,heat given to the system $\Delta Q = 20 \ cal = 20 	imes 4.2 \ J = 84 \ J$. Work done $ON$ the system is $50 \ J$,which means work done $BY$ the system $\Delta W = -50 \ J$. Substituting these values into the equation: $84 \ J = \Delta U + (-50 \ J)$. Therefore,$\Delta U = 84 \ J + 50 \ J = 134 \ J$.

Similar Questions

The resultant gate and its Boolean expression for the given circuit is

$A$ horizontal straight wire $20\, m$ long extending from east to west is falling with a speed of $5.0\, m/s$,at right angles to the horizontal component of the earth's magnetic field $0.30 \times 10^{-4}\, Wb/m^2$. The instantaneous value of the $e.m.f.$ induced in the wire will be.....$mV$.

Identify the product in the following reaction:
$Phenol + CHCl_3 + NaOH \rightarrow \text{Product}$

What is known as 'Butter of Tin'?

Which of the following is Potash Alum?

Vedclass Test Series

Exam Paper Generator

Online Exam Module