The S-O and P-O bond order in SO_4^{2-} and P | vedclass

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Question

(B) The bond order can be calculated using the formula: $Bond \ Order = \frac{	ext{Total number of bonds}}{	ext{Total number of resonating structure

Vedclass · Accepted Answer

$1.5 \& 1.25$

Vedclass · Answer

(B) The bond order can be calculated using the formula: $Bond \ Order = \frac{	ext{Total number of bonds}}{	ext{Total number of resonating structures or terminal atoms}}$.For $SO_4^{2-}$,there are $6$ bonds distributed over $4$ oxygen atoms,so $Bond \ Order = \frac{6}{4} = 1.5$.For $PO_4^{3-}$,there are $5$ bonds distributed over $4$ oxygen atoms,so $Bond \ Order = \frac{5}{4} = 1.25$.Thus,the bond orders are $1.5$ and $1.25$ respectively.

The $S-O$ and $P-O$ bond order in $SO_4^{2-}$ and $PO_4^{3-}$ are respectively:

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