The $EMF$ of a hydrogen electrode in terms of $pH$ is (at $1 \ atm$ pressure).
- A$E_{H_{2}} = \frac{RT}{F} \times pH$
- B$E_{H_{2}} = \frac{RT}{F} \cdot \frac{1}{pH}$
- C$E_{H_{2}} = \frac{2.303 RT}{F} pH$
- D$E_{H_{2}} = -0.0591 \ pH$
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