(C) The structure is $CH \equiv C-CH=CH_2$. According to $IUPAC$ rules for naming hydrocarbons containing both double and triple bonds,if both are at

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(C) The structure is $CH \equiv C-CH=CH_2$. According to $IUPAC$ rules for naming hydrocarbons containing both double and triple bonds,if both are at the same position from either end,the double bond is given priority in numbering. Numbering from right to left: $CH_2(1)=CH(2)-C(3) \equiv CH(4)$. The double bond is at position $1$ and the triple bond is at position $3$. Therefore,the name is but$-1-$ene$-3-$yne.

Class 11 Chemistry 8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds Nomenclature of organic compounds

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The $IUPAC$ name of the compound having the formula $CH \equiv C-CH=CH_2$ is

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A
$1-$butyne$-3-$ene
B
but$-1-$yne$-3-$ene
C
but$-1-$ene$-3-$yne
D
$3-$butene$-1-$yne

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8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds

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Nomenclature of organic compounds

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The $IUPAC$ name of the compound shown in the image is:

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The $IUPAC$ name of the given structure is:
$HOOC-CH_2-C(OH)(COOH)-CH_2-COOH$

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Match the structures in Column-$I$ with their $\text{IUPAC}$ names in Column-$II$.

Column-$I$ (Structure) Column-$II$ ($\text{IUPAC}$ Name)

$A$. $3-$bromocyclohexanol $1$. $2,5$-dimethylhexane-$1,3$-diol

$B$. $CH_3-C(Br)=C(CH_3)-CH_2OH$ $2$. $3$-bromocyclohexanol

$C$. $CH_3-CH(CH_3)-CH_2-CH(OH)-CH(CH_2OH)-CH_3$ $3$. hex-$1$-en-$3$-ol

$D$. $CH_2=CH-CH(OH)-CH_2-CH_2-CH_3$ $4$. $2$-bromo-$3$-methylbut-$2$-en-$1$-ol

Column-$I$ (Structure)	Column-$II$ ($\text{IUPAC}$ Name)
$A$. $3-$bromocyclohexanol	$1$. $2,5$-dimethylhexane-$1,3$-diol
$B$. $CH_3-C(Br)=C(CH_3)-CH_2OH$	$2$. $3$-bromocyclohexanol
$C$. $CH_3-CH(CH_3)-CH_2-CH(OH)-CH(CH_2OH)-CH_3$	$3$. hex-$1$-en-$3$-ol
$D$. $CH_2=CH-CH(OH)-CH_2-CH_2-CH_3$	$4$. $2$-bromo-$3$-methylbut-$2$-en-$1$-ol