The IUPAC name of the compound CH_3-CH=CH-CH= | vedclass

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(B) The compound is $CH_3-CH=CH-CH=CH-C \equiv C-CH_3$.$1$. The longest carbon chain contains $8$ carbon atoms,so the root name is $octa$.$2$. Numberi

Vedclass · Accepted Answer

$2,4-$octadiene$-6-$yne

Vedclass · Answer

(B) The compound is $CH_3-CH=CH-CH=CH-C \equiv C-CH_3$.$1$. The longest carbon chain contains $8$ carbon atoms,so the root name is $octa$.$2$. Numbering the chain from the left gives the double bonds positions at $2$ and $4$,and the triple bond position at $6$.$3$. Numbering from the right gives the triple bond position at $2$ and the double bonds at $4$ and $6$.$4$. According to $IUPAC$ rules,when both double and triple bonds are present,the lowest locant set is preferred. Comparing the sets $(2, 4, 6)$ and $(2, 4, 6)$,we apply the rule that double bonds get priority over triple bonds for the lower locant if there is a tie in the set.$5$. Thus,the correct name is $Octa-2,4-diene-6-yne$.

The $IUPAC$ name of the compound $CH_3-CH=CH-CH=CH-C \equiv C-CH_3$ is:

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