The activation energy for a reaction at the t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The Arrhenius equation is given by $k = A e^{-E_a / RT}$.Here,$k$ is the rate constant,$A$ is the Arrhenius factor (frequency factor),$E_a$ is the

Vedclass · Accepted Answer

$10^{-1}$

Vedclass · Answer

(A) The Arrhenius equation is given by $k = A e^{-E_a / RT}$.Here,$k$ is the rate constant,$A$ is the Arrhenius factor (frequency factor),$E_a$ is the activation energy,$R$ is the gas constant,and $T$ is the temperature.We are given $E_a = 2.303 \ RT \ J \ mol^{-1}$.Substituting the value of $E_a$ into the Arrhenius equation:$k = A e^{-(2.303 \ RT) / RT}$$k = A e^{-2.303}$Since $e^{-2.303} = 10^{-1}$ (because $\ln(10) = 2.303$,so $e^{2.303} = 10$,which implies $e^{-2.303} = 1/10 = 10^{-1}$),$k = A 	imes 10^{-1}$.Therefore,the ratio of the rate constant to the Arrhenius factor is $k/A = 10^{-1}$.

The activation energy for a reaction at the temperature $T \ K$ was found to be $2.303 \ RT \ J \ mol^{-1}$. The ratio of the rate constant to Arrhenius factor is

Similar Questions

The maximum possible number of real roots of the equation $x^5 - 6x^2 - 4x + 5 = 0$ is

If one of the roots of $\left|\begin{array}{lll}3 & 5 & x \\ 7 & x & 7 \\ x & 5 & 3\end{array}\right|=0$ is $-10$,then the other roots are

Which of the following is not a characteristic property of chemical equilibrium?

The $P-V$ diagram of a diatomic gas is a straight line passing through the origin. The molar heat capacity of the gas in the process will be:

The transition from the state $n=3$ to $n=1$ in a hydrogen-like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from:

Vedclass Test Series

Exam Paper Generator

Online Exam Module