The adjoining diagram shows the electric lines of force emerging from a charged body. If the electric fields at $A$ and $B$ are $E_A$ and $E_B$ respectively and the distance between them is $r$,then
- A$E_A > E_B$
- B$E_A < E_B$
- C$E_A = E_B$
- D$E_A > \frac{E_B}{r^2}$
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Consider three point charges $-2Q$, $Q$ and $-Q$ and three surfaces $S_1$, $S_2$ and $S_3$. Match the entries of List-$I$ with that of List-$II$ using Gauss's Law. List-$I$ List-$II$ $(a)$ Net flux through $S_1$ $(i)$ $\frac{-2Q}{\epsilon_0}$ $(b)$ Net flux through $S_2$ (ii) $\frac{-Q}{\epsilon_0}$ $(c)$ Net flux through $S_3$ (iii) Zero
| List-$I$ | List-$II$ |
| $(a)$ Net flux through $S_1$ | $(i)$ $\frac{-2Q}{\epsilon_0}$ |
| $(b)$ Net flux through $S_2$ | (ii) $\frac{-Q}{\epsilon_0}$ |
| $(c)$ Net flux through $S_3$ | (iii) Zero |
MediumKCET 2026
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View SolutionThe distribution of some charges on two Gaussian surfaces $A$ and $B$ are as shown in the figure. If $\phi_A$ and $\phi_B$ are electric fluxes linked with the surfaces $A$ and $B$ respectively,then $\frac{\phi_A}{\phi_B}=$
Discuss some points about Gauss's law.
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View SolutionIf the radius of the spherical Gaussian surface is increased,then the electric flux due to a point charge enclosed by the surface:
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