The amount of work done in forming a soap fil | vedclass

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Question

(A) soap film has two surfaces (one on each side). Therefore,the total change in surface area $\Delta A$ is twice the area of the film.Given: Surface

Vedclass · Accepted Answer

$6 	imes 10^{-4}\,J$

Vedclass · Answer

(A) soap film has two surfaces (one on each side). Therefore,the total change in surface area $\Delta A$ is twice the area of the film.Given: Surface tension $T = 3 	imes 10^{-2}\,N/m$.Area of one side of the film $A = 10\,cm 	imes 10\,cm = 0.1\,m 	imes 0.1\,m = 0.01\,m^2 = 100 	imes 10^{-4}\,m^2$.Total change in surface area $\Delta A = 2 	imes A = 2 	imes 100 	imes 10^{-4}\,m^2 = 200 	imes 10^{-4}\,m^2$.The work done $W$ is equal to the surface energy $E$,given by $W = T 	imes \Delta A$.$W = (3 	imes 10^{-2}\,N/m) 	imes (200 	imes 10^{-4}\,m^2) = 600 	imes 10^{-6}\,J = 6 	imes 10^{-4}\,J$.

The amount of work done in forming a soap film of size $10\,cm \times 10\,cm$ is (Surface tension $T = 3 \times 10^{-2}\,N/m$).

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