The amplification factor of a triode is $18$ and its plate resistance is $8 \times 10^{3} \ \Omega$. $A$ load resistance of $10^{4} \ \Omega$ is connected in the plate circuit. The voltage gain will be

On applying a potential of $-1 \ V$ at the grid of a triode,the following relation between plate voltage $V_p$ $(V)$ and plate current $I_p$ (in $mA$) is found:
$I_p = 0.125 V_p - 7.5$
If on applying $-3 \ V$ potential at the grid and $300 \ V$ potential at the plate,the plate current is found to be $5 \ mA$,then the amplification factor of the triode is:

In the grid circuit of a triode,a signal $E = 2\sqrt{2} \cos(\omega t)$ is applied. If the amplification factor $\mu = 14$ and the plate resistance $r_p = 10\,k\Omega$,then the root mean square $(RMS)$ current flowing through the load resistance $R_L = 12\,k\Omega$ will be.......$mA$.

The plate characteristic curve of a diode in the space charge limited region is as shown in the figure. The slope of the curve at point $P$ is $5.0 \, mA/V$. The static plate resistance of the diode will be ...... $\Omega$.

Which of the following are triode constants?

The voltage gain of a triode depends upon