The angle between the line joining the points $(1, -2)$ and $(3, 2)$ and the line $x + 2y - 7 = 0$ is

Statement $(A)$ : The line $2x + y + 6 = 0$ is perpendicular to the line $x - 2y + 5 = 0$ and the second line passes through $(1, 3)$.
Reason $(R)$ : The product of the slopes of perpendicular lines is $-1$.

The angle between the straight lines $3x + 4y + 9 = 0$ and $x - 7y - 22 = 0$ is

If the equation of a line having a slope $m$ $(m \in \mathbb{Z})$,passing through $(1, 1)$ and making an angle of $\tan^{-1}\left(\frac{5}{7}\right)$ with the line $x + y - 3 = 0$ is $ax + y + c = 0$,then $ac =$

The equation of one of the straight lines which passes through the point $(1, 3)$ and makes an angle of $\tan^{-1}(\sqrt{2})$ with the straight line $y + 1 = 3\sqrt{2}x$ is:

The angle $\theta$ between the lines $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ is given by: