(C) The given equation is $x^2 + 2xy - y^2 = 0$. Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we get $a = 1$,$h = 1$,and $b = -1$. Th

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(C) The given equation is $x^2 + 2xy - y^2 = 0$. Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we get $a = 1$,$h = 1$,and $b = -1$. The condition for the lines to be perpendicular is $a + b = 0$. Here,$a + b = 1 + (-1) = 0$. Since the condition $a + b = 0$ is satisfied,the lines are perpendicular to each other. Therefore,the angle between the pair of lines is $\pi/2$.

Class 11 Mathematics Pair of straight lines Angle between the pair of straight lines, Condition for parallel and perpendicular lines

Easy

The angle between the pair of lines given by the equation $x^2 + 2xy - y^2 = 0$ is

A
$\pi/3$
B
$\pi/6$
C
$\pi/2$
D
$0$

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Pair of straight lines

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Angle between the pair of straight lines, Condition for parallel and perpendicular lines

The equation $x^2 + k_1 y^2 + k_2 xy = 0$ represents a pair of perpendicular lines,if

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The angle between the lines represented by $x^2 + xy = 0$ is .....$^o$

Easy

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If the slope of one of the pair of lines represented by $2x^2 + 3xy + Ky^2 = 0$ is $2$,then the angle between the pair of lines is

DifficultAP EAMCET 2017

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The lines $ax^2+2hxy+by^2=0$ are at right angles if

MediumAP EAMCET 2020

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If the angle $2 \theta$ is acute,then the acute angle between the pair of straight lines $x^2(\cos \theta - \sin \theta) + 2xy \cos \theta + y^2(\cos \theta + \sin \theta) = 0$ is:

DifficultTS EAMCET 2002

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The angle between the pair of lines given by the equation $x^2 + 2xy - y^2 = 0$ is

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The equation $x^2 + k_1 y^2 + k_2 xy = 0$ represents a pair of perpendicular lines,if

The angle between the lines represented by $x^2 + xy = 0$ is .....$^o$

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