The angle of dip at a place is 40.6^circ and | vedclass

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(D) The vertical component of the earth's magnetic field is given by the formula: $V = I \sin \phi$,where $I$ is the total intensity and $\phi$ is the

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$9.2 	imes 10^{-5} 	ext{ Tesla}$

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(D) The vertical component of the earth's magnetic field is given by the formula: $V = I \sin \phi$,where $I$ is the total intensity and $\phi$ is the angle of dip.Given: $V = 6 	imes 10^{-5} 	ext{ Tesla}$ and $\phi = 40.6^\circ$.Rearranging the formula to solve for $I$: $I = \frac{V}{\sin \phi}$.Substituting the values: $I = \frac{6 	imes 10^{-5}}{\sin 40.6^\circ}$.Using $\sin 40.6^\circ \approx 0.65$,we get: $I = \frac{6 	imes 10^{-5}}{0.65} \approx 9.23 	imes 10^{-5} 	ext{ Tesla}$.Thus,the total intensity is approximately $9.2 	imes 10^{-5} 	ext{ Tesla}$.

The angle of dip at a place is $40.6^\circ$ and the intensity of the vertical component of the earth's magnetic field $V = 6 \times 10^{-5} \text{ Tesla}$. The total intensity of the earth's magnetic field $(I)$ at this place is:

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