The angle of elevation of a tower from a distance of $100 \ m$ from its foot is $30^{\circ}$. Then the height of the tower is (in $m$):

  • A
    $100 \sqrt{3}$
  • B
    $\frac{50}{\sqrt{3}}$
  • C
    $50 \sqrt{3}$
  • D
    $\frac{100}{\sqrt{3}}$

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