The angle of elevation of the top of a hill f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $h$ be the height of the hill and $O$ be the foot of the hill on the horizontal plane.Since the angle of elevation from each vertex $A, B, C$

Vedclass · Accepted Answer

$\frac{a}{2} 	an \alpha \operatorname{cosec} A$

Vedclass · Answer

(B) Let $h$ be the height of the hill and $O$ be the foot of the hill on the horizontal plane.Since the angle of elevation from each vertex $A, B, C$ is $\alpha$,we have $OA = OB = OC = h \cot \alpha$.This implies that $O$ is the circumcentre of $	riangle ABC$ with circumradius $R = h \cot \alpha$.In any triangle $ABC$,the circumradius $R$ is given by $R = \frac{a}{2 \sin A}$.Equating the two expressions for $R$: $h \cot \alpha = \frac{a}{2 \sin A}$.Therefore,$h = \frac{a 	an \alpha}{2 \sin A} = \frac{a}{2} 	an \alpha \operatorname{cosec} A$.

The angle of elevation of the top of a hill from each of the vertices $A, B, C$ of a horizontal triangle is $\alpha$. The height of the hill is

Similar Questions

In a rectangle,if the angle between a diagonal and a side is $30^{\circ}$ and the length of the diagonal is $6 \text{ cm}$,the area (in $\text{cm}^2$) of the rectangle is:

The angle of elevation of the sun when the length of the shadow of a pole is equal to its height is

The angle of elevation of a tower from a distance of $100 \ m$ from its foot is $30^{\circ}$. Then the height of the tower is (in $m$):

$ABCD$ is a rectangle where the ratio of the lengths of $AB$ and $BC$ is $3:2$. If $P$ is the midpoint of $AB$,then the value of $\sin(\angle CPB)$ is

The angle of elevation of the top of an unfinished tower at a point $120 \ m$ from its base is $45^{\circ}.$ How much higher (in $m$) must the tower be raised so that its angle of elevation is $60^{\circ}$ at the same point?

Vedclass Test Series

Exam Paper Generator

Online Exam Module